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Transcript of 1 Press Ctrl-A ©G Dear 2010 – Not to be sold/Free to use Area and Perimeter of Irregular Blocks...
![Page 1: 1 Press Ctrl-A ©G Dear 2010 – Not to be sold/Free to use Area and Perimeter of Irregular Blocks Stage 6 - Year 11 Applied Mathematic (Preliminary General.](https://reader035.fdocuments.net/reader035/viewer/2022072010/56649ddd5503460f94ad4dd0/html5/thumbnails/1.jpg)
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Press Ctrl-APress Ctrl-A©G Dear 2010 – Not to be sold/Free to use
Area and Area and PerimeterPerimeter
of Irregular of Irregular BlocksBlocks
Stage 6 - Year 11Stage 6 - Year 11
Applied Mathematic(Preliminary General 1)
![Page 2: 1 Press Ctrl-A ©G Dear 2010 – Not to be sold/Free to use Area and Perimeter of Irregular Blocks Stage 6 - Year 11 Applied Mathematic (Preliminary General.](https://reader035.fdocuments.net/reader035/viewer/2022072010/56649ddd5503460f94ad4dd0/html5/thumbnails/2.jpg)
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If you are doing building, landscaping or some other activity you may need to find the perimeter or area of an irregular block of land.
Regular IrregularEnd ofSlide
![Page 3: 1 Press Ctrl-A ©G Dear 2010 – Not to be sold/Free to use Area and Perimeter of Irregular Blocks Stage 6 - Year 11 Applied Mathematic (Preliminary General.](https://reader035.fdocuments.net/reader035/viewer/2022072010/56649ddd5503460f94ad4dd0/html5/thumbnails/3.jpg)
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Surveyor’s Notebook.This is a diagrammatic representation.
Transverse
Irregular blockof land.
010m
12m 20m
25m
25m10m
10
35
50
12 20
5m20m
45
25
20
Surveyors Notebook.
End ofSlide
![Page 4: 1 Press Ctrl-A ©G Dear 2010 – Not to be sold/Free to use Area and Perimeter of Irregular Blocks Stage 6 - Year 11 Applied Mathematic (Preliminary General.](https://reader035.fdocuments.net/reader035/viewer/2022072010/56649ddd5503460f94ad4dd0/html5/thumbnails/4.jpg)
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0.5x20x5
0.5x10x12
Rectangle
T1 = = 60
T2 =0.5x10x20 = 100
T3 = = 50
T4 =0.5x15x25 = 187.5
TR =0.5x25x(25+12)= 465.5
RE =20x35 = 700
AreaTrap=0.5xhx(a+b)
Finding the Area
10m
12m 20m
25m
25m
10m
5m20m
End ofSlide
Triangle 1
T1
Triangle 2
T2
Triangle 3T3
Triangle 4
T4
Trapezium
TRRE
AreaTriangle=0.5xbxhAreaRectangle= LxBTotal Area =1563m2
![Page 5: 1 Press Ctrl-A ©G Dear 2010 – Not to be sold/Free to use Area and Perimeter of Irregular Blocks Stage 6 - Year 11 Applied Mathematic (Preliminary General.](https://reader035.fdocuments.net/reader035/viewer/2022072010/56649ddd5503460f94ad4dd0/html5/thumbnails/5.jpg)
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Finding the Perimeter
10m
12m 20m
25m
25m
10m
5m20m
End ofSlide
T1 T2
T3
T4
TRRE
T1: c12= 102+122=244c1≈15.6
T2: c22=102+202=500 c2≈22.4
T3: c32= 52+202=425 c3≈20.6
T4: c42=152+252=850 c4≈29.2
TR: cT2=132+252=794 c4≈28.2
13m
RE: cR2=35 c4≈35
Total =151 mc2 = a2 + b2
![Page 6: 1 Press Ctrl-A ©G Dear 2010 – Not to be sold/Free to use Area and Perimeter of Irregular Blocks Stage 6 - Year 11 Applied Mathematic (Preliminary General.](https://reader035.fdocuments.net/reader035/viewer/2022072010/56649ddd5503460f94ad4dd0/html5/thumbnails/6.jpg)
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Finding the AreaHouse
Press
![Page 7: 1 Press Ctrl-A ©G Dear 2010 – Not to be sold/Free to use Area and Perimeter of Irregular Blocks Stage 6 - Year 11 Applied Mathematic (Preliminary General.](https://reader035.fdocuments.net/reader035/viewer/2022072010/56649ddd5503460f94ad4dd0/html5/thumbnails/7.jpg)
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Finding the AreaWe want to concrete the driveway.If the concrete is 30cm thick thenhow much concrete do we need?
End ofSlide
![Page 8: 1 Press Ctrl-A ©G Dear 2010 – Not to be sold/Free to use Area and Perimeter of Irregular Blocks Stage 6 - Year 11 Applied Mathematic (Preliminary General.](https://reader035.fdocuments.net/reader035/viewer/2022072010/56649ddd5503460f94ad4dd0/html5/thumbnails/8.jpg)
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Finding the AreaDraw the line shown below.Divide in half,and half again.
End ofSlide
Simpson’s Rule:A ≈ h÷3(dfirst+4dmiddle+dlast)
h=6m
h=6m
df=0m
dm=3m
dL=2.5m
![Page 9: 1 Press Ctrl-A ©G Dear 2010 – Not to be sold/Free to use Area and Perimeter of Irregular Blocks Stage 6 - Year 11 Applied Mathematic (Preliminary General.](https://reader035.fdocuments.net/reader035/viewer/2022072010/56649ddd5503460f94ad4dd0/html5/thumbnails/9.jpg)
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End ofSlide
Simpson’s Rule:A ≈ h÷3(dfirst+4dmiddle+dlast)
h=6m
h=6m
df=0m
dm=3m
dL=2.5m
A ≈ 6÷3 x (0 + 4x3 + 2.5)
h=6m
h=6m
dF=2.5m
dm=2.8m
dL=0m+ 6÷3 x (2.5 + 4x2.8 + 0)≈ 56.4 m2
V ≈ 56.4 m2x .3 m
≈ 16.92 m3
≈ 17 m3