1 5.0 引言 5.1 轨道, 相互作用与自旋 5.2 原子和分子的磁矩 5.3 晶体的磁矩 5.4...
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Transcript of 1 5.0 引言 5.1 轨道, 相互作用与自旋 5.2 原子和分子的磁矩 5.3 晶体的磁矩 5.4...
![Page 1: 1 5.0 引言 5.1 轨道, 相互作用与自旋 5.2 原子和分子的磁矩 5.3 晶体的磁矩 5.4 晶体的磁各向异性 5.5 习题 5. 磁性与电子态.](https://reader033.fdocuments.net/reader033/viewer/2022050700/56649f505503460f94c72e51/html5/thumbnails/1.jpg)
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5.0 引言5.1 轨道 , 相互作用与自旋5.2 原子和分子的磁矩5.3 晶体的磁矩5.4 晶体的磁各向异性5.5 习题
5. 磁性与电子态
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General remarksUniaxial cases Cubic crystalsWhy success limited
Outline
![Page 3: 1 5.0 引言 5.1 轨道, 相互作用与自旋 5.2 原子和分子的磁矩 5.3 晶体的磁矩 5.4 晶体的磁各向异性 5.5 习题 5. 磁性与电子态.](https://reader033.fdocuments.net/reader033/viewer/2022050700/56649f505503460f94c72e51/html5/thumbnails/3.jpg)
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Decoupling of Spin from Orbit
Even for a spin-dependent Exc, such as Von Barth and Hedin (1972),
Vxc = dExc/d = Vxc
()+ Vxcm
(,m)
The spin-up and spin-down states are decoupled. Total energy depends only on the magnitude of spin polarization, m, but independent of its direction.
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Spin-orbit Coupling Causes Anisotropy
Spin-orbit coupling
Hsl = [(1/4c2r) V/r] l(r) = r l(r)
Total energy variation
Esl() = E(H0+Hsl) E(H0)
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Perturbation Analysis
First order energyE() = <o|l|o> because <o|l|o>=0
Second (even) order energy,
E()= 2|<o|l|e>|2 / ((o)-(e)) + h.o.t
Mostly between spin-down bands
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Directional Dependence
Due to orbital character of the o-e pairs near Fermi surface
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Perpendicular AnisotropyD.S.Wang et al, PRB47, 14932, 1993
Fe film: coupling <5|lz|5*>=<xz|lz|yz>
causes perpendicular anisotropy
Singularity occurs when |e (o)-e (e)| <
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In-plane AnisotropyD.S.Wang et al, JMMM 129, 344, 1994
Co film: coupling
<5|ly|1>=<xz|ly|z2> <5*|lx|1>=<yz|lx|z2>
causes in-plane anisotropy
Singularity occurswhen |e (o)-e (e)| <
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Experiments vs
Theory
D.S.Wang et al. JMMM 140, 643, 1
995
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Anisotropy vs Band Filling
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Anisotropy of X-Co-XD.S.Wang PRB48, 15886, 1993
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Ni Layers on Cu Substrate J.Henk et al, PRB59, 9332 (1999)
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Ni Layers on Cu Substrate J.Henk et al, PRB59, 9332 (1999)
For fct, the bulk contribution is nearly correct, but contribution of the sub-surface layer seems wrong.
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Distorted Cubic Crystals
T.Burkert et al.PRB 69, 104426 (2004)
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Cubic Crystals – Early Empirical
Authors E(001)-E(111) in eV/atom Remarks
bcc Fe fcc Co fcc Ni
Experiments 1.4 1.8 2.7
Kondorskii et al
/JETP36,188(1973) x x 1.3 Empirical
Fritsche et al
/J.Phys.F17,943(1987) 7.4 x 10.0
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Cubic Crystals - LSDA Authors E(001)-E(111) in eV/atom Remarks bcc Fe fcc Co fcc Ni Experiment 1.4 1.8 2.7 Daalderop et al/PRB41,11919(1990) 0.5 x 0.5 Strange et al/Physica B172,51(1991) 9.6 x 10.5 Trygg et al/PRL75,2871(1995) 0.5 0.5 0.5 Razee at al/PRB56,8082(1997) 0.95 0.86 0.11 Halilov et al/PRB57,9557(1998) 0.5 0.3 0.04 2.6 2.4 1.0 scaling
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Cubic Crystals – LSDA+OP
Authors E(001)-E(111) in eV/atom Remarks
bcc Fe fcc Co fcc Ni
Experiment 1.4 1.8 2.7
Trygg et al
/PRL75,2871(1995) 1.8 2.2 0.5 OP
Yang et al.
/PRL87,216405(2001) U=1.2 x U=1.9 in eV
J=0.8 x J=1.2 in eV
Xie et al
/PRB69,172404(2004) U=1.15 U=1.41 U=2.95 in eV
J=0.97 J=0.83 J=0.28 in eV
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Ab Initio Attempt - Summary
• Bulk uniaxial cases are good
• Surface (interface) layers are fair
• Cubic crystals are poor
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Uniaxial Case: Two <o|*|e> Pairs
Reconsider the second order perturbation, E()= 2|<o|l|e>|2 / ((e)-(o))It holds only when (e)(o) > and
.For uniaxial cases, the regular part is in 2nd
order (2/ )! When (e)(o) < degenerate perturbati
on applies, E() | <o|l|e>|
and (2 / | k(o)k(e)| ).Singular at those k points. Total contribution
is in 3rd order (/ )!.
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Cubic Case: Two <o|*|e> Pairs
The second order perturbation, E()= 2|<o|l|e>|2 / ((e)-(o))is isotropic. For cubic case, the regular part
of anisotropy goes to E() 4|<l>|4 / ((e)-(o))3
and . The contribution is in the 4th order (2/ )!
The singular part with,
E() | <o|l|e>|
and (2 / | k(o)k(e)| )Singular at those k points. Total contributio
n is in 3rd order (/ )!.
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Challenge in Cubic Case
• Count the correlation in acceptable accuracy between the nearly degenerate pairs of empty and occupied states around Fermi surface!.
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Concluding Comment
One can not claim understand unless he can calculate !
- J.C.Slater