...NS 28 - 2015 - ,Js91 2,25) (aq) / cc cc 2(g) (aq) 104 C mol-I - vm L.morl . JS -2 0,75 At=25min...

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Transcript of ...NS 28 - 2015 - ,Js91 2,25) (aq) / cc cc 2(g) (aq) 104 C mol-I - vm L.morl . JS -2 0,75 At=25min...

Page 1: ...NS 28 - 2015 - ,Js91 2,25) (aq) / cc cc 2(g) (aq) 104 C mol-I - vm L.morl . JS -2 0,75 At=25min 4,75) oz.... C6H5COOH/C6H5CC)O- 250C H =122gmoFl : MC H5COO ) M(C2H50H) = 46g mol
Page 2: ...NS 28 - 2015 - ,Js91 2,25) (aq) / cc cc 2(g) (aq) 104 C mol-I - vm L.morl . JS -2 0,75 At=25min 4,75) oz.... C6H5COOH/C6H5CC)O- 250C H =122gmoFl : MC H5COO ) M(C2H50H) = 46g mol
Page 3: ...NS 28 - 2015 - ,Js91 2,25) (aq) / cc cc 2(g) (aq) 104 C mol-I - vm L.morl . JS -2 0,75 At=25min 4,75) oz.... C6H5COOH/C6H5CC)O- 250C H =122gmoFl : MC H5COO ) M(C2H50H) = 46g mol
Page 4: ...NS 28 - 2015 - ,Js91 2,25) (aq) / cc cc 2(g) (aq) 104 C mol-I - vm L.morl . JS -2 0,75 At=25min 4,75) oz.... C6H5COOH/C6H5CC)O- 250C H =122gmoFl : MC H5COO ) M(C2H50H) = 46g mol
Page 5: ...NS 28 - 2015 - ,Js91 2,25) (aq) / cc cc 2(g) (aq) 104 C mol-I - vm L.morl . JS -2 0,75 At=25min 4,75) oz.... C6H5COOH/C6H5CC)O- 250C H =122gmoFl : MC H5COO ) M(C2H50H) = 46g mol
Page 6: ...NS 28 - 2015 - ,Js91 2,25) (aq) / cc cc 2(g) (aq) 104 C mol-I - vm L.morl . JS -2 0,75 At=25min 4,75) oz.... C6H5COOH/C6H5CC)O- 250C H =122gmoFl : MC H5COO ) M(C2H50H) = 46g mol
Page 7: ...NS 28 - 2015 - ,Js91 2,25) (aq) / cc cc 2(g) (aq) 104 C mol-I - vm L.morl . JS -2 0,75 At=25min 4,75) oz.... C6H5COOH/C6H5CC)O- 250C H =122gmoFl : MC H5COO ) M(C2H50H) = 46g mol

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Cambridge International Examinations Cambridge Pre-U ...Q is made by mixing 50.0 cm3 of 0.100 mol dm −3 HF(aq) with 50.0 cm3 of 0.100 mol dm −3 NaF(aq) and has a pH of 3.20. If

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… one contains 0.2 mol of solute particles, which co tains 0.1 mol of solute particles, and which contains som where between 0.1 and 0.2 mol of solute particles? (a) Cr2(S04)3(aq)

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Find more free educational resources at …...CuS04(aq) + Mg(s) Cu(s) + MgS04(aq) . When an excess of magnesium was added to 100 cm3 of 0.1 mol dm 3 copper(ll) sulphate, the temperature

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20112018151309-0001 · A student titrated an ethanoic acid solution, CH3COOH (aq), against 50.0 cm3 of 0.995 mol dm 3 sodium hydroxide, NaOH (aq), to determine its concentration.

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Aula #07 · A Comparison of DH and DU DH 2Na (s) + 2H 2 O (l) 2NaOH (aq) + H2 (g) DH = -367.5 kJ/mol DU DH = DU + pDV DU = DH-pDV DU ≡DH-Dn(g) RT = -367.5 - 2.5 = -370.0 kJ/mol

Aula #07 · A Comparison of DH and DU DH 2Na (s) + 2H 2 O (l) 2NaOH (aq) + H2 (g) DH = -367.5 kJ/mol DU DH = DU + pDV DU = DH-pDV DU ≡DH-Dn(g) RT = -367.5 - 2.5 = -370.0 kJ/mol

Writing Net Ionic Equations - PC\|MACimages.pcmac.org/SiSFiles/Schools/SC/Georgetown/WaccamawHigh… · AgC1(s) + Na+(aq) + N03-(aq) Net Ionic Equations AgN03(aq) + NaC1(aq) + NaN03(aq)

Writing Net Ionic Equations - PC\|MACimages.pcmac.org/SiSFiles/Schools/SC/Georgetown/WaccamawHigh… · AgC1(s) + Na+(aq) + N03-(aq) Net Ionic Equations AgN03(aq) + NaC1(aq) + NaN03(aq)