& GUIDED QUESTIONS MATH VOCABULARY DAY 53. Table of ContentsDatePage 3/6/13 Guided Question 106...
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Transcript of & GUIDED QUESTIONS MATH VOCABULARY DAY 53. Table of ContentsDatePage 3/6/13 Guided Question 106...
&GUIDED QUESTIONS
MATH VOCABULARY
DAY 53
NEXT,TABLE OF CONTENTS
Table of ContentsDate Page
3/6/13 Guided Question 1063/6/13 Math Vocabulary 105
NEXT,MATH VOCABULARY
3/6/13 105Math Vocabulary
triangle based pyramid – 4 faces, 6 edges, and
square based pyramid – 5 faces, 8 edges, and
5 vertices.
4 vertices.
NEXT,INDEX
Sstandard form 5sum 5
symbol 57
skip counting 25square units 37
square 73sphere 101square based pyramid 105
69two dimensional63third47triple
tenths 3
T
71triangle79trapezoid89three-dimensional
105triangle based pyramid
NEXT,GUIDED QUESTION
3/6/13 106Guided Question
Question of the Day:
There are 24 hours in a day and 365 days ina year. Which is the best estimate of thenumber of hours in a year?
A 12,000 hours
B 8,000 hours
C 390 hours
D 380 hours
3/6/13 106Guided QuestionThere are 24 hours in a day and 365 days ina year. Which is the best estimate of thenumber of hours in a year?
A 12,000 hours
B 8,000 hours
C 390 hours
D 380 hours
This is an ESTIMATION (ROUNDING) question. You needto round each number to its highest place value. Thehighest place value for 24 is the TENS PLACE, so 24rounds to 20. The highest place value for 365 is the
You need to MULTIPLY (x) 400 and 20. Ignoreall the zeros and just multiply (x) 4 and 2. 4 x 2 = 8.Then count all the zeros in the problem. There are 3
365 400zeros. Put 3 zeros on the end of 8 to make it 8,000.8,000 is your answer.
24 20
HUNDREDS PLACE, so 365 rounds to 400.
The Answer is
8,000
400 x 20 = think 4 x 2 = 8 so 4 0 0 x 2 0 = 8, 0 0 0
REMEMBERIf you fall behind
use my WEB PAGE to fill in the missing parts. We will take a JOURNAL Quiz every Friday, for a grade.