دوائر التبريد.doc
description
Transcript of دوائر التبريد.doc
( )
( )Refrigeration cycle
1- 2- 3- 4-
( 1 ) Pev
( 2 ) Pc ( 3 ) Pc ( 4 ) Pev
- . h= hg - X h = hf +X * hfg h = h sp
h = hf h = h
= 3.517 m ( h h ) = h h C.O.P = ( 1 )h h
= m = m ( h h )
= m ( h h ) ( - )m ( h h ) = 3.517 m ( h h ) 3600 24
= 333 1000 = tan / day ---------------------------------------------------------------------------------------
1 :- 12 4.914 bar 15
1.004bar .
.
0.4 kg/sec
h = hf + X * hfg 50.10 = 8.86 + X * 165.34 = 50.10 8.86
X = = 0.249 165.34 = m ( h h ) = 0.4 ( 174.20 50.10 ) = 49.64 kw m ( h h ) = =
3.517
49.64
= 3.517
14.11= 2 :-
2.465 bar 9.134bar 50C .
0.6kg/mean 1- - / /
- m = 0.6 / 60 = 0.01 kg / sec m ( h h ) = = 0.01 ( 1600 1427.9 ) = 1.721 kw = m ( h h ) = 0.01 ( 1600 284.6 ) =
= 13.154 kJ/ sec - = m ( h h )= 0.01 ( 1427.9 284.6 ) = 11.433 KJ/sec 3 :- 12 0.8071 6.516 bar 240 kg / main
- (m ) - 15C -
- = 240 / 60 = 4 KJ / sec m ( h h ) =
4 = m ( 171.90 59.70 )
4 m = =0.035 kg /sec ( 171.90 59.70 ) - m ( h h ) =
= 0.035 ( 208.50 171.90 ) = 1.281 kw- h h C.O.P =h h 171.90 59.70 C.o.p = = 3.06208.50 171.90 4 :- , 12 15 5.673 bar 2.191bar
= 10 kw
1-
2- (m (-
= 10kw X
= h = hf + X * hfg
54.87 = 26.87 + X * 156.32
54.87 26.87
0.179= = X156.32 = m ( h h ) =
10 = m ( 206.32 183.19 )
10 m= = 0.434 kg/sec 206.32 183.19 - h h C.O.P = h h 183.19 54.87
C.O.P = = 5.54
206.32 183.19 5 :- ( ) 30kg/mean 2.077bar 10.34bar 50C
.
1-
2- KW & T.O.R 3-
0.5 kg/sec m= 30kg/mean=
Power = m ( h h ) 1- Kw 91.3 = ( 1422.7 1605.3 Power = 0.5 ( R.C 2-
R.C = m ( h h )
R.C = 0.5 (1422.7 303.7) = 559.5 KW
159 T.O.R R.C = Q c.d 3-Q c.d = ( h h )
1301.6 = ( 303.7 1605.3 ) Q c.d = 6 :- 2.077bar 10.34bar
50C
1- C.O.P 2- X
1- C.O.P = ?? ?? = X
1- h h C.O.P = h h 1422.7 303.7 6.12= = C.O.P 1605.3 1422.7 2-
h = hf + X * hfg 303.7 = 98.8 + X * 1323.9 303.7 98.8 = X * 1323.9 303.7 98.8
= 0.1547 =X 1323.9 _1269832730.unknown
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