© Boardworks Ltd 20131 of 8 This icon indicates the slide contains activities created in Flash....
-
Upload
irene-pitts -
Category
Documents
-
view
220 -
download
0
Transcript of © Boardworks Ltd 20131 of 8 This icon indicates the slide contains activities created in Flash....
© Boardworks Ltd 20131 of 8
This icon indicates the slide contains activities created in Flash. These activities are not editable.
For more detailed instructions, see the Getting Started presentation.
This icon indicates teacher’s notes in the Notes field.
© Boardworks Ltd 20132 of 8
Finding side lengths
If we are given one side and one acute angle in a right-angled triangle, we can use one of the three trigonometric ratios to find the lengths of other sides.
56°
x12 cm
To find the length of the side oppositethe angle, given the hypotenuse, use:
sin θ =opposite
hypotenuse
sin 56° =x
12
x = 12 × sin 56°
= 9.95 cm
Find x to 2 decimal places.
© Boardworks Ltd 20133 of 8
Finding angles
We are given the lengths of the sides opposite and adjacent to the angle, so we use:
tan θ =oppositeadjacent
tan θ =85
= 57.99° (to 2 d.p.)
θ5 cm
8 cm
θ = tan–1 (8 ÷ 5)
Find θ to 2 decimal places.
© Boardworks Ltd 20136 of 8
The inverse of sin
To work this out use the sin–1 key on the calculator.
sin–1 0.5 = 30°
sin–1 is the inverse of sin. It is sometimes called arcsin.
30° 0.5
sin
sin–1
sin θ = 0.5, what is the value of θ?
© Boardworks Ltd 20137 of 8
The inverse of cos
To work this out use the cos–1 key on the calculator.
cos–1 0.5 = 60°
cos–1 is the inverse of cos. It is sometimes called arccos.
60° 0.5
cos
cos–1
cos θ = 0.5, what is the value of θ?