§ 5 法布里 — 珀罗干涉仪
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Transcript of § 5 法布里 — 珀罗干涉仪
5
G1,G2,h-G1,G2,h-L2
II
R=90% i
n
n0n0n ,r, t n n0r, t90%0.9%0.73%1%0.81%0.66% F P= (2 / ) = (2/)2nhcos i
:A0=0n0n n0
r = - r1- r2 = tt
1R 2,IT+IR=I0 3 R, R. IT/I0 1R 2,IT+IR=I0 3 R, R.
1
RITmax=I0 = 2m sin /2 = 0;IRmin=0
=(2m+1) sin /2=1ITmin= (1-R)2 I0 /(1+R)2 RITminIRmax= 4RI0/(1+R)2 R IRmax
2RR
R1 (1-R) 1
R1 (1-R) 1
R 1, F()= 4R/(1-R)2>>1 sin2( /2),IT/I02mIT.
:
:
F-P F-P F-P 1 2 3 4
R T nhR
n0n ngh i = 0 R=
F-Pngn n0n0 n r t n n0 rt n ng r2 t2 R =
73
1
F-PF-P
F-P i = 0=2m =2nh=m (m=012) ITmax= I0 2nh=2.4m, Itmax?
7 ,
10 nh, m 2TM TM= Itmax/I0 (30%)
m ITmax=I0 =2m m IT= I0/2 =2m /2 3