第 3 章 时域分析法
description
Transcript of 第 3 章 时域分析法
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3 ,
(3.1)
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, ,
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1. 2. 3. 4. 5. MATLAB
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3.1
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12 1 2(3.2)(3.3) (3.2) (3.3)
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3.2
T
3.2.1
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(3.4) t T 3.1 3.1
3.1 (3.4)
t0T2T3T4T5T00.6320.8650.9500.9820.9931
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3.1
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1(3.4)3.1 (1) (2) t=T T0.6320.632T (3) 3T4T95%98% T (4)
t = 0
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(5) (3.4)
tT 3.2 ,
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3.2
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3.2.2
(3.5)3.3 3.5
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3.3
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TT
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3.2.3
(3.6)3.4 (3.6)
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3.4
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3.2.4
(3.7)
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(3.8) (3.7)(3.8)
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3.3
T
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0
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(2) =1
(3) >1
(4) =0
(5)
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3.3.1
(3.9)
- 1.0
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3.5 (3.10) (3.10)(3.11)
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3.6 3.5
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3.6
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2.=1 2-4
3.7 (3.12)
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3.7
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3.>1
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3.8
(3.13)
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3.8
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4.=0
3.9 (3.14)
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3.9
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0.40.80.40.8 3.2
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3.2
>1 =1 0
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3.2
>1 =1 0
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3.2
>1 =1 0
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3.1 1
2 (3.7)
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3.3.2 1. 3.10 N 1 10%90% 2
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3 3.10
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4 5 N N N
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2. 1 (3.11)
- 0
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2 (3.11)
0
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3 (3.18) ; 3.3
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3.3
(3.18)3.3 =0.40.8 4 3.11
00.10.20.30.40.50.60.70.80.9110072.952.737.225.416.39.54.61.50.20
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0
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=0.05, =0.02 =0.707 0.707
3.11
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5 N N N (3.21) =0.05, =0.02
N N N
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N 0.40.8
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3.4
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(3.22)
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1(3.22)s 2(3.22)s
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s3.13as1s23.13b 3(3.22)
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3.13 a)
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3.13 b)
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3.5 3.5.1 3.14 3.14
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1.
2.
3. (3.23) (3.24)
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4. (3.25)(3.24)(3.23)(3.25)
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(3.26) (3.26) 5.
(3.27)
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3.5.2 (3.28) (3.28)(3.27) (3.29) 3.14 (3.26)
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(3.30) (3.30)(3.29) (3.31)
3.3 3.15 (3.32)
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3.15 3.3
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3.5.3 1. 3.14 1 (3.31)
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2 (3.31) (3.33)
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(3.34) 3 (3.31)
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(3.35)
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2. 3.14
(3.36) 0 (3.36)
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(3.37) 0 (3.38) (3.39)
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3. 10 0
2
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3
4. 1
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0 0 03.160
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3.16 0
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2 0 0 3.170
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3.17
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3 0 0 3.18 3.40
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3.4 (1) (2) (3) 3.18
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(4) sL
3.4
0 0 00
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3.4 3.19
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1
ABC 2a3.19 3.4 a)b)
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a a
a 3b
b b
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3.5.4 2 2.49 1. 2.49
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2. 2.49
(3.41) (3.40)
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3.
3.5 3.20K1 K2 TMKcRCM
(3.42)
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3.20 3.5
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K1
K3
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3.6 3.6.1 1. 3.21aABBACAA 3.21bA
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AA 3.21 a
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3.21 b
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2.
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3. (1)
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(2) (3) (4) (5)
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3.6.2
(3.43)
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(3.43)
s (3.44) (3.46) (3.44) (3.45)
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(3.55)
(3.47)
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[s][s]
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[s] [s] (3.47)
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3.6.3 41884E. J. Routh 1.
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(3.49) (3.48)
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(1) (2)
-1
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2. (3.50)
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n n+1n+1
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3.6
4-25-25500[s]
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3. (1) (n=2) (3.51)
(2) (n=3) (3.52)
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3.22 3.7
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3.7 3.22K
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4. (1) 3.8
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[s] (2)
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3.9
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[s]
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3.7 MATLABControl Systems Toolbox3.5 00MATLAB3.6
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3.5
impulse impulsenum,den impulsenum,den,t t step Stepnum,den stepnum,den,t t lsim lsimnum,den,u,t) u t
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3.6 3.10
roots roots(den) denden pzmap pzmapnum,den xo
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(1) MATLABnum=[2 20 50];den=[1 15 84 223 309 240 100];t=(0:0.1:20);figure(1);impulse(num,den,t);%Impulse Responsefigure(2);step(num,den,t);%Step Responsefigure(3);u1=(t);%Ramp. Inputhold on;plot(t,u1);lsim(num,den,u1,t);%Ramp. Responsegtext('t');
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figure(4);u2=(t*t/2);%Acce. Inputhold on;plot(t,u2);lsim(num,den,u2,t); %Acce. Responsegtext('t*t/2');
(2)3.23 a)3.23 3.10
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b)3.23 3.10
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c)3.23 3.10
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3.23 3.10d)
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3.11
(1)MATLAB den=[1 2 3 4 5 6 7 8 9]; roots(den) (2)ans = -1.2888 + 0.4477i -1.2888 - 0.4477i -0.7244 + 1.1370i -0.7244 - 1.1370i 0.1364 + 1.3050i
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0.1364 - 1.3050i0.8767 + 0.8814i0.8767 - 0.8814i 43.12
(1)MATLABnum=[3.12*10^5 6.25*10^6];den=[1 1.0*10^2 8.0*10^3 4.4*10^5 6.24*10^6]; [p,z]=pzmap(num,den);pzmap(num,den);
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title('Pole-Zero Map');hold on; (2) p =-10.0000 +71.4143i-10.0000 -71.4143i-60.0000 -20.0000 z = -20.0321 43.24
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3.24 3.12
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3.6
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3.6
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3.6
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3.6
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3.6