Factor.1. 2. 3.

Warm – up #4

Factor.1. = 3x(2x – 1)2. == (x – 5)(x + 5)

Warm – up #4 Solutions

x 5

3. = 3(16== 3(4(4== 3(2x – y)(2x + y)(4

Warm – up #4 Solutions

2x y

4 𝑦 2

Homework Log

Fri

11/6

Lesson 4 – 4

Learning Objective: To factor difference and sum of cubes & by grouping

Hw: Factoring WS 2

11/6/15 Lesson 4 – 4 Factoring Day 2

Algebra II

To factor difference of cubes To factor sum of cubes To factor by grouping

Learning Objective

Difference of Squares

Sum of Squares

Can’t be factored!

Factoring

Difference of Cubes

Sum of Cubes

Factoring

Pull out the cube rootsSquare the first termChange the SignFirst times the second termPlus the last term squared

Difference & Sum of Cube “Song”

1. == (2x – 1)

2. == (3x – 2)

Difference of Cubes

2x 1

3x 2

(4 + 2x+ 1)

(9 + 6x+ 4)

3. == (4x + 5)

4. == (x+6y)

Sum of Cubes

4x 5

x 6y

(16 - 20x + 25)

( - 6xy + )

5. == ( + 1)( - +1)== (x + 1)(-+1)

Sum of Cubes

𝑥3 1

x 1

Factor By GroupingMainly used when there are 4 terms

Group the first two terms & the last two terms

Factor from each group“Combine” like terms

Factor By Grouping

Factor6. = 2x(2xy – 3)

7. = x(x – 1)

Review Factoring

8. = x(3x + 2y)+5(2y + 3x)

=

Factor by Grouping

(x + 5)(3x + 2y)9. = (7y – 6)- 1(7y - 6)

= ((7y – 6) = (7y – 6)(x + 1)(x – 1)

10. 32ax + 12bx – 48ay – 18by= 2(16ax + 6bx – 24ay - 9by)= 2(2x(8a + 3b) – 3y(8a + 3b))

= 2

Factor by Grouping

(2x – 3y)(8a + 3b)

11. 30ac + 80bd + 40ad + 60bc= 10(3ac + 8bd + 4ad + 6bc)

= 10(3ac + 4ad + 8bd + 6bc)= 10(a(3c + 4d) + 2b(4d + 3c))

= 10

Factor by Grouping

(a + 2b)(3c + 4d)

12. = (x – 3)+1(x – 3)

=

Factor

(x – 3)(+ 1)

13. = 2()= 2(= 2 ((x – 8)

= 2(x – 8)(x + 2)(x – 2)

14. = 8(== 8(x – 1)( + x + 1)

Factor

x 1

15. == (6x + 4)( - 24x+16)= 2(3x + 2)4(9= 8(3x + 2)(9

OR from 8(27=

= 8(3x + 2)(9

Factor

6x 4

3x 2

Factor

What’s the difference in your answers?

Ticket Out the Door

Assignment:

Factoring WS 2