Post on 12-Apr-2017
Vedic MathematicsCultural Computing Initiatives
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The answer is divided into partsThe answer is divided into parts
Number of parts in the answer=Number of parts in the answer=(No. of digits in multiplicand (No. of digits in multiplicand + No. of digits in multiplier)-1+ No. of digits in multiplier)-1
Each part is product or sum of product of digits in Each part is product or sum of product of digits in multiplicand & multiplier.multiplicand & multiplier.
In the answer each part should contain only one digit. The In the answer each part should contain only one digit. The extra digits are added to the immediate left.extra digits are added to the immediate left.
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Answer is divided into 3 parts Answer is divided into 3 parts (2+2)-1=3 (2+2)-1=3
The pattern for each part is given below :The pattern for each part is given below :
RPRPLPLP MPMP
RP represents Units place RP represents Units place MP represents Tens placeMP represents Tens placeLP represents Hundreds place LP represents Hundreds place
Here,Here,
Each dot (Each dot () represent single digit in the number & line jointly ) represent single digit in the number & line jointly represents the no’s to be multiplicationrepresents the no’s to be multiplication
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2 31 2
RP
6
RP =RP =X
3x2 =3x2 =66
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2 31 2
RPMP
7
MP :MP :
X
(3x1(3x1))
= 4+3=7= 4+3=7++ (2x2) (2x2)
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2 31 2
LP RPMP
22x12x1
X=2=2 LP : LP :
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2 31 2
LP RPMP
2LP :LP :
Ans: Ans: 276 276
X
7 6
RP : 3x2=6 RP : 3x2=6
MP :MP : (3x1)(3x1) = 4+3=7= 4+3=7++ (2x2) (2x2)
=2 =2 2x12x1
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3 2
4 121112
RP : 1x2=2 RP : 1x2=2
MP : (3x1) + (4x2) =3+8=11 MP : (3x1) + (4x2) =3+8=11
LP : (3x4)=12 LP : (3x4)=12
Ans: Ans: 1312 1312
Note:Note: RP & MPRP & MP should have only one digit so extra digit is carried & added to should have only one digit so extra digit is carried & added to LPLP
1
X
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4 3
3 5152912
RP : 3x5=15 15
MP : (3x3) + (4x5) =9+20=29MP : (3x3) + (4x5) =9+20=29
LP : (3x4)=12 LP : (3x4)=12
Ans: Ans: 1505 1505
Note:Note: RP & MPRP & MP should have only one digit so extra digit is carried & added to should have only one digit so extra digit is carried & added to LPLP
12
X
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2 3
4 515228
RP : 3x5=15 15
MP : (2x5) + (3x4) =10+12=22MP : (2x5) + (3x4) =10+12=22
LP : (2x4)=8 LP : (2x4)=8
Ans: Ans: 1035 1035
Note:Note: RP & MPRP & MP should have only one digit so extra digit is carried & added to should have only one digit so extra digit is carried & added to LPLP
12
X
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3 4
4 4162412
RP : 4x4=16 16
MP : (3x4) + (4x3) =12+12=24MP : (3x4) + (4x3) =12+12=24
LP : (3x4)=12 LP : (3x4)=12
Ans: Ans: 1456 1456
Note:Note: RP & MPRP & MP should have only one digit so extra digit is carried & added to should have only one digit so extra digit is carried & added to LPLP
12
X
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2
372
RP : 1 x 3= 3
MP : (2x3)+(1x1) = 6 + 1= 7 MP : (2x3)+(1x1) = 6 + 1= 7
LP : (2x1)=2 LP : (2x1)=2
Ans:Ans:
X
19 = 2 1
131
Convert Vinculum to Normal
& 7 = 1 3
11 3333
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4
12120
RP : 3 x 4= 12
MP : (4x4)+(3x5) =16+15=1MP : (4x4)+(3x5) =16+15=1
LP : (4x5)=20 LP : (4x5)=20
Ans: Ans: 1998 1998
X
37 = 4 3
345
Convert Vinculum to Normal= 2002
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4
2512
RP : 1 x 2= 2
MP : (4x2)+(1x3) = 8+3= 5 MP : (4x2)+(1x3) = 8+3= 5
LP : (4x3)=12 LP : (4x3)=12
Ans: Ans: 1148 1148
X
28 = 3 2
123
Convert Vinculum to Normal
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5
42420
RP : 1 x 4= 4
MP : (5x4)+(1x4) = 20+4= 2 4 MP : (5x4)+(1x4) = 20+4= 2 4
LP : (5x4)=20 LP : (5x4)=20
Ans: Ans: 1764 1764
X
49 = 5 1
144
Convert Vinculum to Normal
36 = 4 4
-2
=1 8 4 4
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4
62220
RP : 2 x 3= 6
MP : (4x3)+(2x5) = 12+10= 2 2 MP : (4x3)+(2x5) = 12+10= 2 2
LP : (4x5)=20 LP : (4x5)=20
Ans: Ans: 1786 1786
X
38 = 4 2
235
Convert Vinculum to Normal
47 = 5 3
-2
=1 8 2 6
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5
8215
RP : 4 x 2= 8
MP : (5x2)+(4x3) = 10+12= 2 MP : (5x2)+(4x3) = 10+12= 2
LP : (5x3)= 15 LP : (5x3)= 15
Ans: Ans: 1472 1472
X
46 = 5 4
423
Convert Vinculum to Normal
=1 5 2 8