Trigonometric Equations. Definition Example: Consider:

Post on 19-Jan-2016

232 views 2 download

Tags:

Transcript of Trigonometric Equations. Definition Example: Consider:

Trigonometric Equations

Definition

A trigonometric equation is an equation that contains a trig expression with a variable, such as .

Example:

A solution to this equation is because

Is the only solution to this equation?

Consider:

This graph shows 5 different solutions to the equation So how can we represent all of the solutions?

Since the period of the sine function is first find all solutions in Those solutions are and .

Any multiple of can be added to these values and the sine is still So, all solutions can be given by with n any integer.

Find 4 more solutions to

Equations involving a Single Trig FunctionTo solve an equation involving a single trig function:1. Isolate the function on one side

of the equation.2. Solve for the variable

Solve:

3sin π‘₯βˆ’2=5sin π‘₯βˆ’1

Solve:

5sin π‘₯=3sin π‘₯+√3

Equations Involving Multiple Angles

tan 3π‘₯=10≀π‘₯<2πœ‹

Solve:

Solve:

,

Trig Equations in Quadratic FormForm: where is a trig function Solve by usual Quadratic

Methodsa. Factorb. Quadratic Formulac. Square Root Method

Solve by factoring:

2π‘π‘œπ‘ 2π‘₯+cos xβˆ’1=0 ,0 ≀π‘₯<2πœ‹

Solve by factoring

2𝑠𝑖𝑛2π‘₯βˆ’3sin π‘₯+1=0 ,0≀π‘₯<360 Β°

Solve

2𝑠𝑖𝑛2π‘₯=sinπ‘₯+3 ,0 ≀π‘₯<2πœ‹

Solve

𝑠𝑖𝑛2π‘₯+3 𝑠𝑖𝑛π‘₯βˆ’5=0 ,0≀ π‘₯<360 Β°

3π‘π‘œπ‘ 2 π‘₯βˆ’4cos π‘₯=βˆ’4Solve

Solve

4 𝑠𝑖𝑛2π‘₯βˆ’1=0 ,0≀ π‘₯<2πœ‹

Solve

4π‘π‘œπ‘ 2π‘₯βˆ’3=0 ,0 ≀π‘₯<360 Β°

Separate Two Functions by Factoring

π‘‘π‘Žπ‘›π‘₯ 𝑠𝑖𝑛2π‘₯=3 tan π‘₯ ,0≀ π‘₯<2πœ‹

Separate by Factoring

𝑠𝑖𝑛π‘₯π‘‘π‘Žπ‘›π‘₯=sinπ‘₯

Solve

π‘‘π‘Žπ‘›2 π‘₯π‘π‘œπ‘ π‘₯=π‘‘π‘Žπ‘›2π‘₯ ,0 ≀π‘₯<360 Β°

Solve

π‘π‘œπ‘‘2π‘₯𝑠𝑖𝑛π‘₯=π‘π‘œπ‘‘2 π‘₯ ,0≀ π‘₯<2πœ‹

Using Identities to Solve Trig Equations (All Solve:

2𝑠𝑖𝑛2π‘₯βˆ’3cosx=0

π‘π‘œπ‘ 2π‘₯+3sin π‘₯βˆ’2=0

cos 2π‘₯+sin π‘₯=0

sin π‘₯cos π‘₯=12

sin π‘₯βˆ’ cos π‘₯=1

cos π‘₯βˆ’sin π‘₯=βˆ’1