Post on 12-Jan-2016
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Stoichiometry
Stoichiometry Steps
1. Balance the equation;Is it
balanced?
Is it balanced?
Mole Box
Grams A
Mol A Mol B
Grams B
Molar Mass of A
Mole Ratio(Balanced Equation)
Molar Mass of B
2. Grams to Moles (Divide by Molar Mass)*Don’t forget to use sig figs!*
27.1 grams of O2 X 1 mole O2 =
32 grams O2
0.847 moles of O2
A sample contains 27.1 g of oxygen. How many moles of oxygen are in this sample?
This is the molar mass of Oxygen. (16.00g X 2)= 32.00g of O2 *THIS IS A ONE STEP PROBLEM!
*
3. Moles to Moles ( Multiply by Mole Ratio)
If you started with 3.50 mol of hydrogen, how many moles of oxygen could be formed?
3.50 mol H2 X 1 mole O2 = 1.75 moles of O2 2 moles H2
4. Mole to Grams (Multiply by Molar Mass)
If you needed to produce 12.2 g of water, how many grams of hydrogen would you need?
12.2 moles of H2O X 2 moles H2 X 2 grams H2 = 24.4 grams of H2 2 moles H2O 1 mole H2
*THIS IS A TWO STEP PROBLEM!*
Molarity
The concentration of a solution in
mol/L = moles of solute 1 L of solution
Finding Moles of a Solution
Use the formula;
cv = nConcentration(mol/L) X Volume(L) = Moles(mol)
Mole Box 2Grams A
Mol A Mol B
Grams B
Litres A Litres B
Molar Mass of A
Mole Ratio(Balanced Equation)
Molar Mass of B
Concentration of A (mol/L)
Concentration of B (mol/L)
Example(Litres A to Grams B)
2 NaOH(aq) + H2SO4(aq) Na2SO4(aq) + 2H2O(l)
15.0 mL of a 1.5 mol/L NaOH solution gives how many grams of H2O?
0.0150 L NaOH X 1.5 mol NaOH X 2 mol H2O X 18g H2O = 1 L NaOH 2 mol NaOH 1 mol H2O
CONVERT! 1 L = X L X= 0.0150 L 1000 mL 15.0 mL 0.4
05 g H2O
*THIS IS A THREE STEP PROBLEM!*
Stoichiometry with Gases
The stoichiometry of gases is based on the ratio between the quantities of gas involved in a chemical reaction. This method is used to predict the quantity
of a reactant or product involved in a chemical reaction in which one of the compounds is
a gas.
Example 1(Litres A to Litres B)
If 7.00 L of H2 gas reacts with Cl2 gas, how many litres of HCl gas would form?
H2 + Cl2 2HCl
7.00 L H2 X 2 L HCl = 14.0 L HCl
1 L H2
Example 2(Grams A to Litres B)
Mg(s) + HCl(aq) MgCl2(aq) + H2(g)
If 17.00 g of Mg reacts, how many millilitres of H2 will form?
17.00 g Mg X 1 mol Mg X 1 mol H2 X 22.4 L H2 = 15.70 L of H2 24.31 g Mg 1 mol Mg 1 mol H2
Convert this answer to millilitres!
1 L = 15.70 L X= 15 700 mL of H21000 mL X mL
Classifying Reactions
1. Combustion= Burning with OxygenTips:If C is in the reactants, CO2 will be a product.
Example:• C + O2 CO2If H2 is in the reactants, H2O will be a product.
Example:• 2H2 + O2 2H2O• CH4 + 2O2 CO2 + 2H2O
2. Synthesis
Simpler reactants combine to make more complex products.
Examples:• Mg + Cl2 MgCl2• CO2 + H2O H2CO3
3. Decomposition
Decomposition is when complex Reactants break down to become
simpler molecules.
Examples: • H2CO3 H2O + CO2• BF3NH3 BF3 + NH3
4. Single Displacement
An element and a compound are required for single displacement. The
element in the reactants will “replace” or “displace” one of the
elements in the compound. *It is important to remember that
metals replace metals only, and non-metals replace non-metals only.
Examples:• A + B B + AC• Na(s) + H2O(l) NaOH(aq) + H2(g)
Example of a Reaction
Burning of methane releases 275 kJ of energy per mole of methane being burned. How many grams of methane must burn in order to produce 1500 kJ of energy?
CH4 + 2O2 CO2 + 2H2O1500 kJ X 1 mole CH4 X 16.04 g CH4 275 kJ 1 mole CH4
= 88
g of
CH4
C = 12.01 12.01 + 1.01(4) = 16.04 g of CH4 H = 1.01
What type of reaction has occurred? Combustion reaction.
Bibliography
• Couture, Ivan, Marie-Eve Lacombe-Harvey, and Genevieve Levasseur-Thériault. Quantum Chemistry Student Textbook. Ed. Marie-Eve Robitaille, Isabel Rusin, and Colleen Ovenden. Trans. Jacquie Charlton, Cristina Cusano, Natasha DeCruz, Joann Egar, and Gwen Schulman. Montreal: Cheneliere Education, 2011. Print.
• Doty, Wendy L. "Stoichiometry Notes." Downey Unified School District. N.p., 2006. Web. 10 Oct. 2012. <http://www.dusd.net/staff/rcramm/Chemistry/Unit_8/Stoichiometery%20Notes.pdf>.