Relations and Functions (Algebra 2)

Analyze and graph relations.

Find functional values.

1) ordered pair2) Cartesian Coordinate3) plane4) quadrant5) relation6) domain7) range

8) function9) mapping10) one-to-one function11) vertical line test12) independent variable13) dependent variable14) functional notation

Relations and Functions Relations and Functions

Animal

Average

Lifetime

(years)

Maximum

Lifetime(years)

Cat 12 28

Cow 15 30

Deer 8 20

Dog 12 20

Horse 20 50

This table shows the average lifetimeand maximum lifetime for some animals.

Animal

Average

Lifetime

(years)

Maximum

Lifetime(years)

Cat 12 28

Cow 15 30

Deer 8 20

Dog 12 20

Horse 20 50

The data can also be represented asordered pairs.

Animal

Average

Lifetime

(years)

Maximum

Lifetime(years)

Cat 12 28

Cow 15 30

Deer 8 20

Dog 12 20

Horse 20 50

The ordered pairs for the data are:

Animal

Average

Lifetime

(years)

Maximum

Lifetime(years)

Cat 12 28

Cow 15 30

Deer 8 20

Dog 12 20

Horse 20 50

(12, 28), (15, 30), (8, 20),

(12, 20), (20, 50)and

Animal

Average

Lifetime

(years)

Maximum

Lifetime(years)

Cat 12 28

Cow 15 30

Deer 8 20

Dog 12 20

Horse 20 50

(12, 28), (15, 30), (8, 20),

(12, 20), (20, 50)and

The first number in each ordered pairis the average lifetime, and the secondnumber is the maximum lifetime.

Animal

Average

Lifetime

(years)

Maximum

Lifetime(years)

Cat 12 28

Cow 15 30

Deer 8 20

Dog 12 20

Horse 20 50

(12, 28), (15, 30), (8, 20),

(12, 20), (20, 50)and

(20, 50)

Animal

Average

Lifetime

(years)

Maximum

Lifetime(years)

Cat 12 28

Cow 15 30

Deer 8 20

Dog 12 20

Horse 20 50

(12, 28), (15, 30), (8, 20),

(12, 20), (20, 50)and

(20, 50)

averagelifetime

Animal

Average

Lifetime

(years)

Maximum

Lifetime(years)

Cat 12 28

Cow 15 30

Deer 8 20

Dog 12 20

Horse 20 50

(12, 28), (15, 30), (8, 20),

(12, 20), (20, 50)and

(20, 50)

averagelifetime

maximumlifetime

Animal Lifetimes

x3010 20 30

Average Lifetime

You can graph the ordered pairs belowon a coordinate system with two axes.

Animal Lifetimes

x3010 20 30

Average Lifetime

(12, 28),

Animal Lifetimes

x3010 20 30

Average Lifetime

(12, 28), (15, 30),

Animal Lifetimes

x3010 20 30

Average Lifetime

(12, 28), (15, 30), (8, 20),

Animal Lifetimes

x3010 20 30

Average Lifetime

(12, 28), (15, 30), (8, 20),

(12, 20),

Animal Lifetimes

x3010 20 30

Average Lifetime

(12, 28), (15, 30), (8, 20),

(12, 20), (20, 50)and

Animal Lifetimes

x3010 20 30

Average Lifetime

(12, 28), (15, 30), (8, 20),

(12, 20), (20, 50)and

Remember, each point in the coordinateplane can be named by exactly one ordered pair and that every ordered pair names exactly one point in the coordinate plane.

Animal Lifetimes

x3010 20 30

Average Lifetime

(12, 28), (15, 30), (8, 20),

(12, 20), (20, 50)and

Remember, each point in the coordinateplane can be named by exactly one ordered pair and that every ordered pair names exactly one point in the coordinate plane.

The graph of this data (animal lifetimes)lies in only one part of the Cartesiancoordinate plane – the part with allpositive numbers.

The Cartesian coordinate system is composed of the x-axis (horizontal),

0 5-50

Origin(0, 0)

and the y-axis (vertical), which meet at the origin (0, 0) and divide the plane intofour quadrants.

0 5-50

Origin(0, 0)

You can tell which quadrant a point is in by looking at the sign of each coordinate of the point.

Quadrant I( +, + )

Quadrant II( --, + )

Quadrant III( --, -- )

Quadrant IV( +, -- )

0 5-50

Origin(0, 0)

You can tell which quadrant a point is in by looking at the sign of each coordinate of the point.

Quadrant I( +, + )

Quadrant II( --, + )

Quadrant III( --, -- )

Quadrant IV( +, -- )

The points on the two axes do not lie in any quadrant.

In general, any ordered pair in the coordinate plane can be written in the form (x, y)

A relation is a set of ordered pairs, such as the one for the longevity of animals.

The domain of a relation is the set of all first coordinates (x-coordinates) from theordered pairs.

The range of a relation is the set of all second coordinates (y-coordinates) from the ordered pairs.

The graph of a relation is the set of points in the coordinate plane corresponding to theordered pairs in the relation.

A function is a special type of relation in which each element of the domain is pairedwith ___________ element in the range.

A function is a special type of relation in which each element of the domain is pairedwith ___________ element in the range.exactly one

A mapping shows how each member of the domain is paired with each member in the range.

Functions

4,2,2,0,1,3

Functions

4,2,2,0,1,3

Domain

Functions

4,2,2,0,1,3

Domain Range

Functions

4,2,2,0,1,3

Domain Range

Functions

4,2,2,0,1,3

Domain Range

Functions

4,2,2,0,1,3

Domain Range

Functions

4,2,2,0,1,3

Domain Range

one-to-one function

Functions

5,4,3,1,5,1

Functions

5,4,3,1,5,1

Domain Range

Functions

5,4,3,1,5,1

Domain Range

Functions

5,4,3,1,5,1

Domain Range

Functions

5,4,3,1,5,1

Domain Range

Functions

5,4,3,1,5,1

Domain Range

function,not one-to-one

Functions

6,3,1,1,0,3,6,5

Functions

6,3,1,1,0,3,6,5

Domain Range

Functions

6,3,1,1,0,3,6,5

Domain Range

Functions

6,3,1,1,0,3,6,5

Domain Range

Functions

6,3,1,1,0,3,6,5

Domain Range

not a function

Functions

6,3,1,1,0,3,6,5

Domain Range

not a function

(-4,3) (2,3)

(-1,-2)

(0,-4)

(3,-3)

State the domain and range of the relation shownin the graph. Is the relation a function?

(-4,3) (2,3)

(-1,-2)

(0,-4)

(3,-3)

The relation is:

{ (-4, 3), (-1, 2), (0, -4), (2, 3), (3, -3) }

(-4,3) (2,3)

(-1,-2)

(0,-4)

(3,-3)

The relation is:

{ (-4, 3), (-1, 2), (0, -4), (2, 3), (3, -3) }

The domain is:

(-4,3) (2,3)

(-1,-2)

(0,-4)

(3,-3)

The relation is:

{ (-4, 3), (-1, 2), (0, -4), (2, 3), (3, -3) }

The domain is:

{ -4, -1, 0, 2, 3 }

(-4,3) (2,3)

(-1,-2)

(0,-4)

(3,-3)

The relation is:

{ (-4, 3), (-1, 2), (0, -4), (2, 3), (3, -3) }

The domain is:

{ -4, -1, 0, 2, 3 }

The range is:

(-4,3) (2,3)

(-1,-2)

(0,-4)

(3,-3)

The relation is:

{ (-4, 3), (-1, 2), (0, -4), (2, 3), (3, -3) }

The domain is:

{ -4, -1, 0, 2, 3 }

The range is:

{ -4, -3, -2, 3 }

(-4,3) (2,3)

(-1,-2)

(0,-4)

(3,-3)

The relation is:

{ (-4, 3), (-1, 2), (0, -4), (2, 3), (3, -3) }

The domain is:

{ -4, -1, 0, 2, 3 }

The range is:

{ -4, -3, -2, 3 }

Each member of the domain is paired with exactly one member of the range,so this relation is a function.

You can use the vertical line test to determine whether a relation is a function.

Vertical Line Test

If no vertical line intersects agraph in more than one point,

the graph represents a function.

Vertical Line Test

If some vertical line intercepts agraph in two or more points, the

graph does not represent a function.

Vertical Line Test

YearPopulation

(millions)

1950 3.9

1960 4.7

1970 5.2

1980 5.5

1990 5.5

2000 6.1

The table shows the population of Indiana over the last severaldecades.

YearPopulation

(millions)

1950 3.9

1960 4.7

1970 5.2

1980 5.5

1990 5.5

2000 6.1

We can graph this data to determine if it represents a function.

YearPopulation

(millions)

1950 3.9

1960 4.7

1970 5.2

1980 5.5

1990 5.5

2000 6.1

7‘600

‘80‘70 ‘000

Population of Indiana

YearPopulation

(millions)

1950 3.9

1960 4.7

1970 5.2

1980 5.5

1990 5.5

2000 6.1

7‘600

‘80‘70 ‘000

Use the verticalline test.

YearPopulation

(millions)

1950 3.9

1960 4.7

1970 5.2

1980 5.5

1990 5.5

2000 6.1

7‘600

‘80‘70 ‘000

YearPopulation

(millions)

1950 3.9

1960 4.7

1970 5.2

1980 5.5

1990 5.5

2000 6.1

7‘600

‘80‘70 ‘000

YearPopulation

(millions)

1950 3.9

1960 4.7

1970 5.2

1980 5.5

1990 5.5

2000 6.1

7‘600

‘80‘70 ‘000

YearPopulation

(millions)

1950 3.9

1960 4.7

1970 5.2

1980 5.5

1990 5.5

2000 6.1

7‘600

‘80‘70 ‘000

YearPopulation

(millions)

1950 3.9

1960 4.7

1970 5.2

1980 5.5

1990 5.5

2000 6.1

7‘600

‘80‘70 ‘000

YearPopulation

(millions)

1950 3.9

1960 4.7

1970 5.2

1980 5.5

1990 5.5

2000 6.1

7‘600

‘80‘70 ‘000

YearPopulation

(millions)

1950 3.9

1960 4.7

1970 5.2

1980 5.5

1990 5.5

2000 6.1

7‘600

‘80‘70 ‘000

YearPopulation

(millions)

1950 3.9

1960 4.7

1970 5.2

1980 5.5

1990 5.5

2000 6.1

7‘600

‘80‘70 ‘000

YearPopulation

(millions)

1950 3.9

1960 4.7

1970 5.2

1980 5.5

1990 5.5

2000 6.1

7‘600

‘80‘70 ‘000

Notice that no vertical line can be drawn thatcontains more than one of the data points.

YearPopulation

(millions)

1950 3.9

1960 4.7

1970 5.2

1980 5.5

1990 5.5

2000 6.1

7‘600

‘80‘70 ‘000

Notice that no vertical line can be drawn thatcontains more than one of the data points.

Therefore, this relation is a function!Therefore, this relation is a function!

12relation Graph the xy

1) Make a table of values.

2) Graph the ordered pairs.

5-4 -2 1 3-3-3

-5 -1 4

5-4 -2 1 3-3-3

-5 -1 4

3) Find the domain and range.

5-4 -2 1 3-3-3

-5 -1 4

Domain is all real numbers.

5-4 -2 1 3-3-3

-5 -1 4

Range is all real numbers.

5-4 -2 1 3-3-3

-5 -1 4

4) Determine whether the relation is a function.

5-4 -2 1 3-3-3

-5 -1 4

5-4 -2 1 3-3-3

-5 -1 4

5-4 -2 1 3-3-3

-5 -1 4

5-4 -2 1 3-3-3

-5 -1 4

5-4 -2 1 3-3-3

-5 -1 4

The graph passes the vertical line test.

5-4 -2 1 3-3-3

-5 -1 4

The graph passes the vertical line test.

For every x value there is exactly one y value,so the equation y = 2x + 1 represents a function.

2relation Graph the 2 yx

5-4 -2 1 3-3-3

-5 -1 4

5-4 -2 1 3-3-3

-5 -1 4

5-4 -2 1 3-3-3

-5 -1 4

Domain is all real numbers,greater than or equal to -2.

5-4 -2 1 3-3-3

-5 -1 4

5-4 -2 1 3-3-3

-5 -1 4

5-4 -2 1 3-3-3

-5 -1 4

5-4 -2 1 3-3-3

-5 -1 4

5-4 -2 1 3-3-3

-5 -1 4

The graph does not pass the vertical line test.

5-4 -2 1 3-3-3

-5 -1 4

The graph does not pass the vertical line test.

For every x value (except x = -2), there are TWO y values, so the equation x = y2 – 2

DOES NOT represent a function.

For every x value (except x = -2), there are TWO y values, so the equation x = y2 – 2

DOES NOT represent a function.

When an equation represents a function, the variable (usually x) whose values makeup the domain is called the independent variable.

The other variable (usually y) whose values make up the range is called the dependent variable because its values depend on x.

Equations that represent functions are often written in function notation.

The equation y = 2x + 1 can be written as f(x) = 2x + 1.

The symbol f(x) replaces the __ ,y and is read “f of x”

The f is just the name of the function. It is NOT a variable that is multiplied by x.

Suppose you want to find the value in the range that corresponds to the element4 in the domain of the function.

f(x) = 2x + 1

This is written as f(4) and is read “f of 4.”

f(x) = 2x + 1

The value f(4) is found by substituting 4 for each x in the equation.

f(x) = 2x + 1

Therefore, if f(x) = 2x + 1

f(x) = 2x + 1

Therefore, if f(x) = 2x + 1Then f(4) = 2(4) + 1

f(x) = 2x + 1

f(4) = 8 + 1

f(x) = 2x + 1

f(4) = 8 + 1

f(4) = 9

f(x) = 2x + 1

f(4) = 8 + 1

f(4) = 9

NOTE: Letters other than f can be used to represent a function.

f(x) = 2x + 1

f(4) = 8 + 1

f(4) = 9

NOTE: Letters other than f can be used to represent a function.

EXAMPLE: g(x) = 2x + 1

Given: f(x) = x2 + 2 and g(x) = 0.5x2 – 5x + 3.5

Find each value.

f(x) = x2 + 2

Find each value.

f(x) = x2 + 2

Find each value.

f(-3) = (-3)2 + 2

f(x) = x2 + 2

Find each value.

f(-3) = (-3)2 + 2

f(-3) = 9 + 2

f(x) = x2 + 2

Find each value.

f(-3) = (-3)2 + 2

f(-3) = 9 + 2

f(-3) = 11

f(x) = x2 + 2

Find each value.

f(-3) = (-3)2 + 2

f(-3) = 9 + 2

f(-3) = 11

g(2.8)

f(x) = x2 + 2

Find each value.

f(-3) = (-3)2 + 2

f(-3) = 9 + 2

f(-3) = 11

g(2.8)

g(x) = 0.5x2 – 5x + 3.5

f(x) = x2 + 2

Find each value.

f(-3) = (-3)2 + 2

f(-3) = 9 + 2

f(-3) = 11

g(2.8)

g(x) = 0.5x2 – 5x + 3.5

g(2.8) = 0.5(2.8)2 – 5(2.8) + 3.5

f(x) = x2 + 2

Find each value.

f(-3) = (-3)2 + 2

f(-3) = 9 + 2

f(-3) = 11

g(2.8)

g(x) = 0.5x2 – 5x + 3.5

g(2.8) = 0.5(2.8)2 – 5(2.8) + 3.5

g(2.8) = 3.92 – 14 + 3.5

f(x) = x2 + 2

Find each value.

f(-3) = (-3)2 + 2

f(-3) = 9 + 2

f(-3) = 11

g(2.8)

g(x) = 0.5x2 – 5x + 3.5

g(2.8) = 0.5(2.8)2 – 5(2.8) + 3.5

g(2.8) = 3.92 – 14 + 3.5

g(2.8) = – 6.58

Given: f(x) = x2 + 2

Find the value.

f(x) = x2 + 2

Find the value.

f(x) = x2 + 2

Find the value.

f( ) = 2 + 23z (3z)

f(x) = x2 + 2

Find the value.

f( ) = 2 + 2

f(3z) = 9z2 + 2

3z (3z)

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Relations and Functions (Algebra 2)

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