Post on 14-Apr-2018
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Adithya Chandrashekharan
WIN: 839136435
ECE-5200, Power Electronics
Fall, 2013
Project #2
Due:10/14/2013
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A three-phase rectifier has a three-phase source of 480 V RMS line-to-line, and
the load is a 25- resistance in series with a 50-mH inductance.
i. Draw the circuit diagram required. Also include SPICE diagramin the final report.
Circuit Diagram:
Spice Diagram:
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ii. Use SPICE to determine(a) DC level of the output voltage=648V
(b) DC of the load current=25.709A
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(c) Average Current in the diodes=8.6351A
RMS Current in the diodes= 15 A
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(d) RMS current in the source=21 A
(e) Apparent power from the source, S= 17.658KVA
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iii. Use SPICE to plot the following:
(a) Output current
(b) Output voltage v
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(c) Diode D1 voltage
(d) Diode D1 current
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(e) Source current
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(f) First ac term (first harmonic) of the loadcurrent=28.29A
(g) the fifth harmonic ac term of the load current.
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First and Fifth harmonic ac term of the loadcurrent
It is clearly seen that the 5th harmonic AC term is (1/5)th of the 1st harmonic ACterm
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P-Spice Circuit to determine the first AC harmonic term:
P-Spice Circuit to determine the first AC harmonic term:
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P-Spice Input File:
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10/09/13 12:06:50 ************** PSpice Lite (Mar 2000) *****************
Profile: "SCHEMATIC1-three phase rectifier" [ E:\important\edu\WMU\4th Sem Fall 2013\Power Electronicssignments\Projec
* CIRCUIT DESCRIPTION
**************************************************************************
reating circuit file "three phase rectifier-schematic1-three phase rectifier.sim.cir"ARNING: THIS AUTOMATICALLY GENERATED FILE MAY BE OVERWRITTEN BY SUBSEQUENT SIMULATIONS
raries:cal Libraries :om [PSPICE NETLIST] section of C:\Program Files\OrcadLite\PSpice\PSpice.ini file:"nom.lib"
lysis directives:N 0 50ms 0 0.00001R 60 10 I(V_Va)BE V(*) I(*) W(*) D(*) NOISE(*)".\three phase rectifier-SCHEMATIC1.net"
INCLUDING "three phase rectifier-SCHEMATIC1.net" ****urce THREE PHASE RECTIFIERN00612 0
0 392 60 0 0 0N00776 0
0 392 60 0 0 -120degV2 N005550 50mH
h N07726 00 5.696 300 0 0 -1.96
N00694 00 392 60 0 0 -240deg
V1 N005550 25N00612 V1 Dbreak0 1 1N00776 V1 DbreakN00694 V1 Dbreak
V2 N00612 DbreakV2 N00776 Dbreakh 1 00 28.29 60 0 0 179.9
V2 N00694 Dbreak5 N07726 0 1
RESUMING "three phase rectifier-schematic1-three phase rectifier.sim.cir" ****
10/09/13 12:06:50 ************** PSpice Lite (Mar 2000) *****************
Profile: "SCHEMATIC1-three phase rectifier" [ E:\important\edu\WMU\4th Sem Fall 2013\Power Electronicssignments\Projec
* Diode MODEL PARAMETERS
**************************************************************************
DbreakIS 10.000000E-15RS .1CJO 100.000000E-15
10/09/13 12:06:50 ************** PSpice Lite (Mar 2000) *****************
Profile: "SCHEMATIC1-three phase rectifier" [ E:\important\edu\WMU\4th Sem Fall 2013\Power Electronicssignments\Projec
: 1
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* INITIAL TRANSIENT SOLUTION TEMPERATURE = 27.000 DEG C
**************************************************************************
E VOLTAGE NODE VOLTAGE NODE VOLTAGE NODE VOLTAGE
1) .0494 ( V1) 335.8800 ( V2) -335.8800 (N00612) 0.0000
694) 339.4800 (N00776) -339.4800 (N07726) -.1948 (N005550) -335.8800
VOLTAGE SOURCE CURRENTSNAME CURRENT
V_Va -6.721E-25V_Vb 2.687E+01V_V5h 1.948E-01V_Vc -2.687E+01V_V1h -4.938E-02
TOTAL POWER DISSIPATION 1.82E+04 WATTS
10/09/13 12:06:50 ************** PSpice Lite (Mar 2000) *****************
Profile: "SCHEMATIC1-three phase rectifier" [ E:\important\edu\WMU\4th Sem Fall 2013\Power Electronicssignments\Projec
* FOURIER ANALYSIS TEMPERATURE = 27.000 DEG C
**************************************************************************
IER COMPONENTS OF TRANSIENT RESPONSE I(V_Va)
COMPONENT = -1.617686E-04
MONIC FREQUENCY FOURIER NORMALIZED PHASE NORMALIZEDNO (HZ) COMPONENT COMPONENT (DEG) PHASE (DEG)
1 6.000E+01 2.829E+01 1.000E+00 1.799E+02 0.000E+002 1.200E+02 1.536E-04 5.429E-06 -8.962E+01 -4.493E+023 1.800E+02 1.751E-04 6.189E-06 -1.719E+02 -7.115E+024 2.400E+02 1.669E-04 5.900E-06 8.158E+01 -6.379E+025 3.000E+02 5.696E+00 2.013E-01 -1.968E+00 -9.013E+026 3.600E+02 3.044E-04 1.076E-05 8.896E+01 -9.902E+027 4.200E+02 4.003E+00 1.415E-01 2.142E+00 -1.257E+038 4.800E+02 1.611E-04 5.694E-06 9.431E+01 -1.345E+039 5.400E+02 1.741E-04 6.155E-06 1.497E+01 -1.604E+0310 6.000E+02 1.596E-04 5.642E-06 -9.437E+01 -1.893E+03
TOTAL HARMONIC DISTORTION = 2.460684E+01 PERCENT
JOB CONCLUDED
TOTAL JOB TIME .95