Presented By: Charbel A. Habib Harpreet Kaur Jassal Hassan A.M. Muhsen.

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Transcript of Presented By: Charbel A. Habib Harpreet Kaur Jassal Hassan A.M. Muhsen.

Presented By:Charbel A. Habib

Harpreet Kaur JassalHassan A.M. Muhsen

OutlineThe Project

Input unit Processing unitControl UnitOutput unit

Future WorkConclusion

The ProjectSystem Architecture

System Architecture

Input Unit

Main Unit(Microcontroller/PC)

Robot (Output Unit)

EOG Sensors(Electrodes)

Amplifier

Process Unit

Control Unit

Filtering

Segmentation

Translation

Comunicator

EOGEOG Signal

EOG: Electrooculogram the recording of the changes in voltage that occur

with the eye position.

o Electro: electricalo Oculo: eyeo Gram: recording

EOGEOG Signal

EOG: Electrooculogram spherical battery

positive terminal: the cornea negative terminal: the retina.

0.4 and 1 mV

EOGEOG Signal

EOGEOG Signal

The signals are measured using EEG disposable electrodes

Input UnitSensors

Amplifier

EOGElectrode signal:

0.4 and 1 mV

This low voltage is not strong neither usable

SOLUTION: ???

EOGAmplifier

Designing an amplifier Requirements:

Total gain of 5000 Cutoff frequency of 25Hz LPF Offset compensation

Amplifier Design

Buffer Amplifier

U1A

LM747AH

4

3

5

2

1

R1

3.3k

R23.3k

1

VCC

12V

nVCC

-12V

VCC

nVCC

V1500mV

0

3

U2A

LM747AH

4

3

5

2

1

R3

3.3k

VCC

12V

VCC

-12V

V2200mV

6

0

VCC

VCC

4

XMM1

2

5

Difference Amplifier

Amplifier Gain = -R2/R1

U3A

LM747AH4

3

5

2

1

VCC

12V

nVCC

-12V

VCC

R4

3.3k

R5

3.3kR83.3k

10

0

R6

33k

R7

33k7

nVCC8

XFG2

XSC3

A B

G

T

XSC1

A B

G

T

0

9

12

11

High Frequency Filter

4th order Butterworth FilterCut off Frequency of Filter

(f0)= 1/(2π*R*C)

R1

10k

R2

10k

R3

10kU3A

LM747AH

4

3

5

2

1

VCC

12V

nVCC

-12V

VCC

nVCC

R4

5.6k

1

R5

10k

R6

10k

R7

10kU1A

LM747AH

4

3

5

2

1

VCC

12V

VCC

-12V R8

5.6k

7VCC

VCC

XFG1

0

XSC1

A B

G

T

0

XSC2

A B

G

T

9

0

C50.47uF-POL

3

4

C10.47uF-POL

2

0

C20.47uF-POL

6

8

C30.47uF-POL

5

0

Low Pass Filter

Summer Amplifier

U1A

LM747AH4

3

5

2

1

VCC

12V

nVCC

-12V

R1

10k

R2

10k

R3

10k

R410k

R5

20K_LINKey = A

50%1

0 2

4

XFG1

XSC1

A B

G

T

5

XSC2

A B

G

T

3

0

VCC

12V

VCC

VCC

12V

VCC

0

Inverting and Non inverting Amplifier + Rectifier

Inverting Amplifier = -R2/R1 & Non Inverting Amplifier = 1+ R2/R1

XFG1

XSC1

A B

G

T

U1A

LM747AH4

3

5

2

1

VCC

12V

nVCC

-12V

R1

3.3k

R2

33k

2

0

XSC2

A B

G

T

R3

10k

0

D2

1N4001GP

6 4

U2A

LM747AH4

3

5

2

1

VCC

12V

nVCC

-12VR4

3.3k

R5

33k

0 3

D1

1N4001GP

5

0

1

XSC3

A B

G

T

R6

10k

7

0

Half Wave Rectifier

Amplifier Implementation

Amplifier Gain

Problems Unavailability of small power supply

Electrodes

Amplifier Vcc supplier

Main UnitProcess Unit

Control Unit

Processing UnitRight side movement of eyes

Left side movement of eyes

Movement of eyes during reading

Upside movement of eyes

Downward movement of eyes

Blinking movement of eyes

Signal ProcessingFiltering (Median Filter)Segmentation (Clustering)

Original Data

Filtered Data

Segmented Data

ProblemsMicrocontroller Delay

Median Filter Window Size

Control Unit

Control Unit

Translation

Comunicator

Control UnitTranslation (PWM)

Center = 128Right & Up = 185Left & Down = 70

CommunicationDirect from Microcontroller

Main Unit

Overall PictureStart

Running Mode

Read Input

Yes

Process input

Send Output

Calibrate

No(Learning Mode)

End

ProblemsCalibration

ADC Delay

Output Unit

Demo

Future WorkOn/Off Mechanism

Real Neck Implementation

Applying to Aesop3000

Conclusion

THANKSAny Questions???