Oct. 29, 2012

AGENDA:1 – Bell Ringer2 – Kinematics

Equations3 – Exit Ticket

Today’s Goal:Students will be able to identify which kinematic equation to apply in each situationHomework

1. Pages 4-5

CHAMPS for Bell Ringer

C – Conversation – No Talking H – Help – RAISE HAND for questionsA – Activity – Solve Bell Ringer on

binder paper. Homework out on desk

M – Materials and Movement – Pen/Pencil, Notebook or Paper

P – Participation – Be in assigned seats, work silently

S – Success – Get a stamp! I will collect!

October 29th (p. 13)

Objective: Students will be able to identify which kinematic equation to apply in each situation

Bell Ringer:Let’s say two people are

racing:The first person has a large

initialvelocity (20 m/s) but a slowacceleration (1 m/s2).

The other has a small initialvelocity (0 m/s) but a largeAcceleration (5 m/s2).Who will win the race and

why?

4 MINUTES REMAINING…

October 29th (p. 13)

Objective: Students will be able to identify which kinematic equation to apply in each situation

Bell Ringer:Let’s say two people are

racing:The first person has a large

initialvelocity (20 m/s) but a slowacceleration (1 m/s2).

The other has a small initialvelocity (0 m/s) but a largeAcceleration (5 m/s2).Who will win the race and

why?

3 MINUTES REMAINING…

October 29th (p. 13)

Objective: Students will be able to identify which kinematic equation to apply in each situation

Bell Ringer:Let’s say two people are

racing:The first person has a large

initialvelocity (20 m/s) but a slowacceleration (1 m/s2).

The other has a small initialvelocity (0 m/s) but a largeAcceleration (5 m/s2).Who will win the race and

why?

2 MINUTES REMAINING…

October 29th (p. 13)

Objective: Students will be able to identify which kinematic equation to apply in each situation

Bell Ringer:Let’s say two people are

racing:The first person has a large

initialvelocity (20 m/s) but a slowacceleration (1 m/s2).

The other has a small initialvelocity (0 m/s) but a largeAcceleration (5 m/s2).Who will win the race and

why?

1minute Remaining…

October 29th (p. 13)

Objective: Students will be able to identify which kinematic equation to apply in each situation

Bell Ringer:Let’s say two people are

racing:The first person has a large

initialvelocity (20 m/s) but a slowacceleration (1 m/s2).

The other has a small initialvelocity (0 m/s) but a largeAcceleration (5 m/s2).Who will win the race and

why?

30 Seconds Remaining…

October 29th (p. 13)

Objective: Students will be able to identify which kinematic equation to apply in each situation

Bell Ringer:Let’s say two people are

racing:The first person has a large

initialvelocity (20 m/s) but a slowacceleration (1 m/s2).

The other has a small initialvelocity (0 m/s) but a largeAcceleration (5 m/s2).Who will win the race and

why?

BELL-RINGER TIME IS

UP!

October 29th (p. 13)

Objective: Students will be able to identify which kinematic equation to apply in each situation

Bell Ringer:Let’s say two people are

racing:The first person has a large

initialvelocity (20 m/s) but a slowacceleration (1 m/s2).

The other has a small initialvelocity (0 m/s) but a largeAcceleration (5 m/s2).Who will win the race and

why?

Shout Outs

Period 5 –Period 7 –

Oct. 29, 2012

AGENDA:1 – Bell Ringer2 – Kinematics

Equations3 – Exit Ticket

Today’s Goal:Students will be able to identify which kinematic equation to apply in each situationHomework

1. Pages 4-5

Week 8

Weekly AgendaMonday – Kinematic Equations ITuesday – Kinematic Equations IIWednesday – Kinematic Equations

IIIThursday – ReviewFriday – Review

Unit Test in 2 weeks!

CHAMPS for Problems p. 4-6

C – Conversation – No Talking unless directed to work in groups

H – Help – RAISE HAND for questionsA – Activity – Solve Problems on Page

4-6M – Materials and Movement –

Pen/Pencil, Packet Pages 4-6P – Participation – Complete Page 4-6S – Success – Understand all

Problems

Notes: Kinematic Equations

The Four Kinematic Equations:vf = vi + aΔt

Δx = viΔt + aΔt2

2vf

2 = vi2 + 2aΔx

Δx = (vf + vi)Δt 2

Solving Kinematics Problems

Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.

Solving Kinematics Problems

Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.

Solving Problems (p. 4)

1. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. What is the final velocity of the Road Runner?

Solving Problems (p. 4)

1. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. What is the final velocity of the Road Runner?

Solving Kinematics Problems

Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.

Solving Problems (p. 4)

1. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. What is the final velocity of the Road Runner?

Solving Problems (p. 4)

1. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. What is the final velocity of the Road Runner?

vi = 0 m/sa = 3 m/s2

Δt = 10 seconds

Solving Kinematics Problems

Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.

Solving Problems (p. 4)

1. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. What is the final velocity of the Road Runner?

vi = 0 m/sa = 3 m/s2

Δt = 10 seconds

Solving Problems (p. 4)

1. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. What is the final velocity of the Road Runner?

vi = 0 m/sa = 3 m/s2

Δt = 10 seconds

vf = ?

Solving Kinematics Problems

Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.

Notes: Kinematic Equations

The Four Kinematic Equations:vf = vi + aΔt

Δx = viΔt + aΔt2

2vf

2 = vi2 + 2aΔx

Δx = (vf + vi)Δt 2

Notes: Kinematic Equations

The Four Kinematic Equations:vf = vi + aΔt

Δx = viΔt + aΔt2

2vf

2 = vi2 + 2aΔx

Δx = (vf + vi)Δt 2

Solving Problems (p. 4)

2. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. How far does the Road Runner travel during the ten second time interval?

Solving Kinematics Problems

Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.

Solving Problems (p. 4)

2. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. How far does the Road Runner travel during the ten second time interval?

Solving Kinematics Problems

Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.

Solving Problems (p. 4)

2. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. How far does the Road Runner travel during the ten second time interval?

Solving Problems (p. 4)

2. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. How far does the Road Runner travel during the ten second time interval?

vi = 0 m/sa = 3 m/s2

Δt = 10 seconds

Solving Kinematics Problems

Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.

Solving Problems (p. 4)

2. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. How far does the Road Runner travel during the ten second time interval?

vi = 0 m/sa = 3 m/s2

Δt = 10 seconds

Solving Problems (p. 4)

2. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. How far does the Road Runner travel during the ten second time interval?

vi = 0 m/sa = 3 m/s2

Δt = 10 seconds

Δx = ?

Solving Kinematics Problems

Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.

Notes: Kinematic Equations

The Four Kinematic Equations:vf = vi + aΔt

Δx = viΔt + aΔt2

2vf

2 = vi2 + 2aΔx

Δx = (vf + vi)Δt 2

Notes: Kinematic Equations

The Four Kinematic Equations:vf = vi + aΔt

Δx = viΔt + aΔt2

2vf

2 = vi2 + 2aΔx

Δx = (vf + vi)Δt 2

Solving Problems (p. 4)

3. A bullet starting from rest accelerates at 40,000 m/s2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun?

Solving Kinematics Problems

Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.

Solving Problems (p. 4)

3. A bullet starting from rest accelerates at 40,000 m/s2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun?

Solving Kinematics Problems

Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.

Solving Problems (p. 4)

3. A bullet starting from rest accelerates at 40,000 m/s2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun?

Solving Problems (p. 4)

3. A bullet starting from rest accelerates at 40,000 m/s2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun?

vi = 0 m/sa = 40,000 m/s2

Δx = 0.5 m

Solving Kinematics Problems

Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.

Solving Problems (p. 4)

3. A bullet starting from rest accelerates at 40,000 m/s2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun?

vi = 0 m/sa = 40,000 m/s2

Δx = 0.5 m

Solving Problems (p. 4)

3. A bullet starting from rest accelerates at 40,000 m/s2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun?

vi = 0 m/sa = 40,000 m/s2

Δx = 0.5 m

vf = ?

Solving Kinematics Problems

Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.

Solving Problems (p. 4)

3. A bullet starting from rest accelerates at 40,000 m/s2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun?

vi = 0 m/sa = 40,000 m/s2

Δx = 0.5 m

vf = ?

Notes: Kinematic Equations

The Four Kinematic Equations:vf = vi + aΔt

Δx = viΔt + aΔt2

2vf

2 = vi2 + 2aΔx

Δx = (vf + vi)Δt 2

Notes: Kinematic Equations

The Four Kinematic Equations:vf = vi + aΔt

Δx = viΔt + aΔt2

2vf

2 = vi2 + 2aΔx

Δx = (vf + vi)Δt 2

Solving Problems (p. 4)

4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car?

Solving Kinematics Problems

Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.

Solving Problems (p. 4)

4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car?

Solving Kinematics Problems

Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.

Solving Problems (p. 4)

4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car?

Solving Problems (p. 4)

4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car?

vi = 20 m/svf = 0 m/sΔt = 4 seconds

Solving Kinematics Problems

Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.

Solving Problems (p. 4)

4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car?

vi = 20 m/svf = 0 m/sΔt = 4 seconds

Solving Problems (p. 4)

4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car?

vi = 20 m/svf = 0 m/sΔt = 4 seconds

a = ?

Solving Kinematics Problems

Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.

Solving Problems (p. 4)

4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car?

vi = 20 m/svf = 0 m/sΔt = 4 seconds

a = ?

Notes: Kinematic Equations

The Four Kinematic Equations:vf = vi + aΔt

Δx = viΔt + aΔt2

2vf

2 = vi2 + 2aΔx

Δx = (vf + vi)Δt 2

Notes: Kinematic Equations

The Four Kinematic Equations:vf = vi + aΔt

Δx = viΔt + aΔt2

2vf

2 = vi2 + 2aΔx

Δx = (vf + vi)Δt 2

Solving Problems (p. 5)

5. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. How far does the car travel before coming to a stop?

Solving Kinematics Problems

Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.

Solving Problems (p. 5)

5. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. How far does the car travel before coming to a stop?

Solving Kinematics Problems

Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.

Solving Problems (p. 5)

6. The USS Enterprise accelerates from rest at 100,000 m/s2 for a time of four seconds. How far did the ship travel in that time?

Exit Ticket (p. 14)

12, Calvin tosses a water balloon to Hobbes. As Hobbes is about to catch it the balloon has a speed of 1 m/s. Hobbes catches the balloon, and the balloon experiences an acceleration of -0.5 m/s2 as it comes to rest. How far did Hobbes' hands move back while catching the balloon?

Write the given variables, the missing variable, and the equation you will use.