Law of cosines

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Transcript of Law of cosines

Law of CosinesLaw of Cosines

Pg 733Pg 733

• Use the Law of Cosines to solve triangles and problems

Previously, we learned the Law of Sines, which as some theorems can, it does have its limitations. To use the Law of Sines we had to know the measures of two angles and any side (AAS or ASA) OR the measures of two sides and an opposite angle (SSA).

If we don’t have either of these scenarios, but instead we have the measures of two sides and the included angle (SAS) or the measures of all the sides and no angles (SSS), we must use the Law of Cosines.

a

b

Law of Cosines: In ABC,

a2 = b2 + c2 – 2bc cos A

b2 = a2 + c2 – 2ac cos B

c2 = a2 + b2 – 2ab cos C

B

A

C

cb

a

Use the Law of Cosines since the measures of two sides and the included angle are known.

Simplify.

Take the square root of each side.

Law of Cosines

Use a calculator.

Answer:

Answer:

Law of Cosines

Simplify.

Solve for L.

Use a calculator.

Subtract 754 from each side.

Divide each side by –270.

Answer:

Answer:

Determine whether the Law of Sines or the Law of Cosines should be used first to solve Then solve Round angle measures to the nearest degree and side measures to the nearest tenth.

Since we know the measures of two sides and the included angle, use the Law of Cosines.

Take the square root of each side.

Use a calculator.

Law of Cosines

Next, we can find If we decide to find we can use either the Law of Sines or the Law of Cosines to find this value. In this case, we will use the Law of Sines.

Cross products

Divide each side by 46.9.

Law of Sines

Take the inverse of each side.

Use a calculator.

Use the Angle Sum Theorem to find

Angle Sum Theorem

Subtract 168 from each side.

Answer:

Determine whether the Law of Sines or the Law of Cosines should be used first to solve Then solve Round angle measures to the nearest degree and side measures to the nearest tenth.

Answer:

Since is an isosceles triangle,

AIRCRAFT From the diagram of the plane shown, determine the approximate exterior perimeter of each wing. Round to the nearest tenth meter.

Cross products

Law of Sines

Simplify.

Divide each side by sin .

Use the Law of Sines to find KJ.

Use the Law of Sines to find .

Cross products

Law of Sines

Solve for H.

Divide each side by 9.

Use a calculator.

Use the Angle Sum Theorem to find

Subtract 95 from each side.

Angle Sum Theorem

Use the Law of Sines to find HK.

Cross products

Law of Sines

Use a calculator.

Divide each side by sin

Answer: The perimeter is about or about 67.1 meters.

The perimeter of the wing is equal to

The rear side window of a station wagon has the shape shown in the figure. Find the perimeter of the window if the length of DB is 31 inches.

Answer: about 93.5 in.