Lakeland Solutions Review

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Lakeland Solutions Review. Click on a question to begin. Question 1. Try Again. Review the definition of Molarity. Try Again. Correct!. Molarity is the moles of solute per liter of solution. Next Question. Question 2. Try Again. - PowerPoint PPT Presentation

Transcript of Lakeland Solutions Review

Lakeland Solutions Review

Click on a question to begin1 6 11

2 7 12

3 8 13

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Molarity is defined as the

A) moles of solute per kilogram of solvent

B) moles of solute per liter of solution

C) mass of a solution D) volume of a solvent

Question 1

Try Again

Try Again

• Review the definition of Molarity

Correct!

• Molarity is the moles of solute per liter of solution

Next Question

Under which conditions of temperature andpressure is a gas most soluble in water?

A) high temperature and low pressure

B) low temperature and low pressure

C) high temperature and high pressure

D) low temperature and high pressure

Question 2

Try Again

Try Again

• Think about the best conditions to keep carbonation in pop

Correct!

• The best conditions are high pressure and low temperature. These produce a situation where the gas will be forced into the liquid

Next Question

What is the molarity of a solution of NaOH if2 liters of the solution contains 4 moles of NaOH?

A) 0.5 M B) 2.0 M

C) 8.0 M D) 80 M

Question 3

Try Again

Try Again

• Molarity is moles of solute per liter of solution

Correct!

• There are 4 moles of solute in 2 liters of solution. Molarity is moles divided by liters so 4/2 = 2 M

Next Question

A substance that conducts an electrical currentwhen dissolved in water is called

A) A catalyst B) A non-electrolyte

C) A metalloid D) An electrolyte

Question 4

Try Again

Try Again

• Review your solutions vocabulary

Correct!

• An electrolyte is a solution that can conduct electricity

Next Question

Compared to a 2.0 M aqueous solution of NaClat 1 atmosphere, a 3.0 M aqueous solution ofNaCl at 1 atmosphere has aA) Lower boiling point and higher

freezing pointB) Lower boiling point and lower freezing point

C) Higher boiling point and lower freezing point

D) Higher boiling point and higher freezing point

Question 5

Try Again

Try Again

• The addition of a solute changes the vapor pressure of a solution. The more solute dissolved, the greater the change in colligative properties.

Correct!

• The 3.0 M solution has more solute dissolved than the 2.0 M solution. This means that there will be a greater boiling point elevation and freezing point depression

Next Question

A 3.0 M HCl(aq) solution contains a total of

A) 3.0 grams of HCl per liter of solution

B) 3.0 grams of HCl per mole of solution

C) 3.0 moles of HCl per liter of solution

D) 3.0 moles of HCl per mole of solution

Question 6

Try Again

Try Again

• Review the definition of molarity

Correct!

• 3.0 M means that there are 3.0 moles per liter of solution

Next Question

What is the total number of grams of HI in0.500 liter of 1.00 M HI?

A) 1.00 g B) 64.0 g

C) 0.5 g D) 128.0 g

Question 7

Try Again

Try Again

• Use the molarity equation to solve for number of moles and then convert to grams

Correct!

• Molarity = moles/liters so 1.00 M = x/0.50 L. X = 0.500 mol. Convert 0.500 mol to grams of HI (mass = 128 g) to get 64 grams.

Next Question

Which 1-molal aqueous solution has the lowestfreezing point?

Question 8

Try Again

Try Again

• The lowest freezing point will have the lowest vapor pressure. The more ions present, the lower the vapor pressure.

Correct!

• The beaker contains the most ions which will reduce vapor pressure the most.

Next Question

What is the molarity of a solution that contains0.50 mole of NaOH in 0.50 liter of solution?

A) 1.00 M B) 0.25 M

C) 2.00 M D) 0.50 M

Question 9

Try Again

Try Again

• Remember that Molarity is moles per liter

Correct!

• 0.50 mol/0.50 liters is 1.00 M

Next Question

What is the total number of moles of solute in2.0 liters of 3.0 M NaOH?

A) 1.0 mole B) 2.0 mole

C) 3.0 mole D) 6.0 mole

Question 10

Try Again

Try Again

• Molarity equals moles of solute divided by liters of solution.

Correct!

• 3.0 M = x/2.0 L so x = (3.0)(2.0) = 6.0 mole

Next Question

Given the Ksp expression: Ksp = [A3+]2 [B2–]3

Which reaction is represented by the expression?

A) A2B3(s) 3A3+(aq) + 2B2–(aq) B) A2B3(s) 2A3+(aq) + 3B2–(aq)

C) A3B2(s) 3A3+(aq) + 2B2–(aq) D) A3B2(s) 2A3+(aq) + 3B2–(aq)

Question 11

Try Again

Try Again

• The exponents in the expression tell you how many of each ion are present in the compound

Correct!

• The exponents in the expression mean that there are 2 A and 3 B in the solid.

Next Question

As the pressure on a gas confined above a liquidincreases, the solubility of the gas in the liquid

A) increases B) decreases

C) Remains the same D) Not enough information

Question 12

Try Again

Try Again

• Think about what is the best way to keep carbonation in pop.

Correct!

• Increasing pressure increases the solubility of a gas in a liquid

Next Question

Which preparation produces a 2.0 M solution ofC6H12O6? [molecular mass = 180.0]

A) 90.0 g of C6H12O6 dissolved in 500.0 mL of solution

B) 90.0 g of C6H12O6 dissolved in 1000. mL of solution

C) 180.0 g of C6H12O6 dissolved in 500.0 mL of solution

D) 180.0 g of C6H12O6 dissolved in 1000. mL of solution

Question 13

Try Again

Try Again

• Convert the grams of sugar to moles and divide by the liters in order to determine molarity

Correct!

• 180 grams of C6H12O6 is equal to 1 mole. 1 mole divided by 0.5 L (500 mL) is 2.0 M.

Next Question

As a solute is added to a solvent, what happens to the freezing point and the boiling point of the solution?

A) The freezing point decreases and the boiling point decreases.

B) The freezing point increases and the boiling point increases.

C) The freezing point increases and the boiling point decreases.

D) The freezing point decreases and the boiling point increases.

Question 14

Try Again

Try Again

• The addition of a solute causes a change in vapor pressure resulting in boiling point elevation and freezing point depression

Correct!

• The addition of a solute causes the boiling point to go up and the freezing point to go down.

Next Question

A bottle of rubbing alcohol is labeled 70% v/v. If the bottle contains 591 mL, how much rubbing alcohol is in the bottle?

A) 591 mL B) 70 mL

C) 413.7 mL D) 177.3 mL

Question 15

Try Again

Try Again

• %v/v = volume of solute x 100 volume of solution

Correct!

• 70 = x x 100 x = 413.7 mL 591

Next Question