Post on 13-Dec-2015
Recall• We know that for a function to
have an inverse that is a function, it must be one-to-one—it must pass the Horizontal Line Test.
Sine Wave• From looking at a sine wave, it is
obvious that it does not pass the Horizontal Line Test.
Sine Wave• In order to pass the Horizontal
Line Test (so that sin x has an inverse that is a function), we must restrict the domain.
• We restrict it to ,
2 2
Sine Wave• Quadrant IV is • Quadrant I is • Answers must be in one of those
two quadrants or the answer doesn’t exist.
,02
0,2
Sine Wave• How do we draw inverse
functions?• Switch the x’s and y’s!Switching the x’s and y’s also
means switching the axis!
Sine Wave• Domain/range of restricted wave?• Domain/range of inverse?
: ,2 2
: 1,1
D
R
: 1,1
: ,2 2
D
R
Inverse Notation• y = arcsin x or y = sin-1 x
• Both mean the same thing. They mean that you’re looking for the angle (y) where sin y = x.
Evaluating Inverse Functions
• Find the exact value of:• Arcsin ½
– This means at what angle is the sin = ½ ?
– π/6– 5π/6 has the same answer, but falls
in QIII, so it is not correct.
Calculator• When looking for an inverse answer
on the calculator, use the 2nd key first, then hit sin, cos, or tan.
• When looking for an angle always hit the 2nd key first.
• Last example: Degree mode, 2nd, sin, .5 = 30.
Evaluating Inverse Functions
• Find the value of:• sin-1 2
– This means at what angle is the sin = 2 ?
– What does your calculator read? Why?
– 2 falls outside the range of a sine wave and outside the domain of the inverse sine wave
Cosine Wave• Quadrant I is • Quadrant II is • Answers must be in one of those
two quadrants or the answer doesn’t exist.
0,2
,2
Graphing Utility: Graph the following inverse functions.
a. y = arcsin x
b. y = arccos x
c. y = arctan x
–1.5 1.5
–
–1.5 1.5
2
–
–3 3
–
Set calculator to radian mode.
Graphing Utility: Approximate the value of each expression.
a. cos–1 0.75 b. arcsin 0.19
c. arctan 1.32 d. arcsin 2.5
Set calculator to radian mode.
Composition of Functions
• Find the exact value of•
• Where is the sine =• Replace the parenthesis in the
original problem with that answer• Now solve
1 2sin sin
2
22 4
sin4 2
2
Example• Find the exact value of
• The sine angles must be in QI or QIV, so we must use the reference angle
•
1 3sin sin
4
2sin
4 2
4
1 13sin sin sin sin
4 4
1 2sin
2
4
Example• Find tan(arctan(-5))
-5• Find
• If the words are the same and the inverse function is inside the parenthesis, the answer is already given!
1 1cos cos
2
12
Example• Find the exact value of• Steps:• Draw a triangle using only the
info inside the parentheses.• Now use your x, y, r’s
to answer the outside term
2tan arccos
3
2
3 5
yt n
52
ax
Last Example• Find the exact value of• Cos is negative in QII and III, but
the inverse is restricted to QII.
1 7tan cos
12
-7
1295ytan
x957