Curvas de Rosa

Post on 07-Feb-2016

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description

calculo vectorial

Transcript of Curvas de Rosa

CURVAS DE ROSA

r=3cos(5t)

r=cos(2t)

r=-2sin(5t)

r=1-2sin(3t)

r=1-2sin(4t)

r=1-2sin(2t)

CIRCULO

r=6

CARDIOIDE

r=1-cos(t)

r=1-sin(t)

ESPIRAL DE ARQUIMIDES

r=15(t)

LIMACON

r=5cost+5

r=3-4cos(t)

r=3-4sin(t)

LEMISCATA

r=5(sin(2t))^0.5 o r=

√5sin 2t

r=5(cos(2t))^0.5 o r=

√5cos2 t

r=5(-cos(2t))^0.5 o r=

√−5cos2 t